Which of the following pair is expected to exhibit the same colour in solution?
Text Solution
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CuCl 2 ; VOC1 2
In CuCl 2 , Cu 2+ has d 9 configuration, exhibit d-d transition and show colour. Similarly in VOC1 2 , V 4+ has d 1 configuration, can exhibit d-d transition and show colour.
MnCl 2 = Pink colour
Zn 2+ 
3d 10 (Colourless)
Hg 2+ 
5d 10 (Colourless)
V = 4s 2 3d 3
V 4+ = 4s° 3d 1 (d - d transition)
Cu +2 = d 9 configuration = 1 - unpaired e - electrons.
Since, in both CuCl 2 and VOC1 2 , Cu 2+ and V 4+ ion contain 1 unpaired electron each, so their colour may be same.
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